The timeout doc said the timeout is checked before polling the future,
but the impl polls the future first and only then checks the delay (see
the Future impl for Timeout, which calls me.value.poll before
poll_delay). Reverse the clause to match the implementation. This is
also what makes the rest of the sentence correct: the future can
complete and exceed the timeout without an error precisely because it is
polled before the timeout is checked.
Co-authored-by: Patrick Wehbe <[email protected]>
